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12n^2+5n-156=0
a = 12; b = 5; c = -156;
Δ = b2-4ac
Δ = 52-4·12·(-156)
Δ = 7513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{7513}}{2*12}=\frac{-5-\sqrt{7513}}{24} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{7513}}{2*12}=\frac{-5+\sqrt{7513}}{24} $
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